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Find the area of a triangle whose two sides are 18 cm and 10 cm and the perimeter is 42cm. hey plz tell me the full solution not only the answer |
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Answer» -STEP explanation:GIVEN,Side a=18cmSide b=10cmPerimeter=42cm=a+b+c:. Putting value42=18+10+c42=28+c42-28=c14=cNow,S=(a+b+c)/2:. Putting valueS=42/2S=21Now according to HERON's formula-Area of a triangle=√{s(s-a)(s-b)(s-c)}:. Putting value=√{21(21-18)(21-10)(21-14)}=√{21(3)(11)(7)}=√4851=21√11cm²I hope this HELPS you (^.^) |
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