Find the area of hexagon ABCDEF in which BL IAD, CM LAD, EN LAD and FP 1 AD such that AP = 6 cm, PL = 2 cm.LN = 8 cm, NM = 2 cm, MD = 3 cm, FP = S cm. EN = 12 cm.BL = 8 cm and CM = 6 cm.

Find the area of hexagon ABCDEF in which BL IAD, CM LAD, EN LAD and

1.	Find the area of hexagon ABCDEF in which BL IAD, CM LAD, EN LAD and FP 1 AD such that AP = 6 cm, PL = 2 cm.LN = 8 cm, NM = 2 cm, MD = 3 cm, FP = S cm. EN = 12 cm.BL = 8 cm and CM = 6 cm.
Answer» -step explanation:The given details are,BL⊥AD, CM⊥AD, EN⊥AD and FP⊥AD $$AP=6 cm, PL= 2 cm, LN=8 cm, NM=2 cm, MD=3 cm, FP=8 cm, EN=12 cm. BL= 8 cm , CM=6cm.AL=AP+PL=6+2=8cmPN=PL+LN=2+8=10cmLM=LN+NM=8+2=10cmND=NM+MD=2+3=5cmBy Using the formula,Area (hex. ABCDEF) =area(△APF)+area(△DEN)+area(△ABL)+area(△CMD)+area(Trap.PNEF)+area(Trap.LMCB)Area of triangle =1/2×base×heightArea of trapezium =1/2×(sum of parallel sides)×height∴lets calculate,Area(△APF)=1/2(AP)×(FP)=1/2×6×8=24cm2 Area(△DEN)=1/2(ND)×(EN)=1/2×5×12=30cm2Area(△ABL)=1/2(AL)×(BL)=1/2×