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Find the area of parallelogram.. |
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Answer» -step explanation:Please refer to the attachment for the figureGiven,BD = 5 cmAB = CD = 4 cmAD = BC = 3 cmAE = 2 cmTo find,Area of the parallelogram ABCDSolution,In this parallelogram ABCD, BD is the diagonal of the parallelogram of length 5 CMIN ∆ABD and ∆BCD,AB = CD = 4 CM AD = BC = 3 cmBD = BD = 5 cm ( Common side )Therefore,By SSS,∆ABD is congruent to ∆BCDAs ∆ABD is congruent to ∆BCD,Therefore,Area of ∆ABD = Area of ∆BCD = kTherefore,Area of parallelogram = Area of ∆ABD + Area of ∆BCD = K + k = 2kIn ∆ ABD,AE is acting as the altitude of the triangleWe know that,Area of triangle = (Base x Altitude)/2Therefore,Area of ∆ABD = ( 5 x 2)/2 = 10/2 = 5 cm²Area of ∆BCD = Area of ∆ABD = 5 cm²Therefore,Area of parallelogram = 5 + 5 = 10 cm² |
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