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Find the area of quadrilateral abcd, I. Which ab=7cm, bc=6cm, cd=12cm, da=15cm and ac=9cm |
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Answer» 74.9761Step-by-step explanation:area of quadrilateral ABCD= Area of triangle ABC + Area of triangle ADCArea of trianlge= sqrt(s(s-a)(s-b)(s-c))FOR area of triangle ABCs=(7+6+9)/2=11area of triangle ABC=sqrt(11(11-7)(11-6)(11-9))=sqrt(440)= 20.9761similarly,area of triangle ADC=54therefore area of quadrilateral ABCD=20.9761+ 54=74.9761ANOTHER WAY...LET it be 2 triangles RATHER than 1 big quadrilateral.ABC = 7/6/9 and ADC = 15/12/9total area= √(11 * 4 * 5 * 2) + (12 * 9) / 2= 2√110 + 54= 74.976177=~ 75 cm^2 |
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