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find the area of the aluminium sheet required to make a cyclindrical container which is open and one side and whose diameter is 42cm and height is 22cm find the approximate area of the aluminium sheet required to make a lid of height 3cm for this container​

Answer»

Step-by-step explanation:

Diameter = 42 cm

Radius = 21 cm

Height = 22 cm

Area of Alumunium SHEET required = CSA + PI

So,

\sf{ \pi r ( 2h + r)}

\sf{ \dfrac{22}{7} \times 21  ( 2(22) + 21)}

So, this gives out 4290 cm²

Now, approximate area of lid = CSA + pi r²

But, height is 3 cm now in this case.

\sf{ \pi r ( 2H + r)}

\sf{ \dfrac{22}{7} \times 21  ( 2(3) + 21)}

This gives out 1782 cm². Hence the answers.



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