Find the area of the following:- e) of trapezium parallel sides are 13 cm and h =12 cmplease solve and answer

Find the area of the following:- e) of trapezium parallel sides are

1.	Find the area of the following:- e) of trapezium parallel sides are 13 cm and h =12 cmplease solve and answer
Answer» Answer 4.0/5 219 Brainly User Given:- ABCD Is a TRAPEZIUM AB = 25 CM DC = 13 cm AD & BC = 15 cm CONSTRUCTION:- Draw CE \|\| AD To FIND :- Area of trapezium ABCD Solution :- ADCE is a parallelogram ( AD \|\| CE & AE \|\| CD). ∴ AE = DC = 13 cm ( Opposite side of parallelogram are equal) BE = AB - AE BE = 25 - 13 BE = 12 cm In ∆ BCE S = a + b + c/2 S = 15 + 15 + 12 /2 S = 21 Area of ∆ BCE = √ s( s - a)(s - b)( s - c ) Area of ∆ BCE = √ 21(21-15)(21-15)(21-12) Area of ∆ BCE = √ 21 × 6 × 6 × 9 Area of ∆ BCE = 18√21 cm^2 -----1 h is the height of ∆ BCE Area of BCE = 1/2 ( Base × Height ) = 1/2(12)(h) = 6h -----2 From 1 & 2 6h = 18√21 => h = 3√21 cm The height of trapezium ABCD is equal to height of ∆ BCE. Area of trapezium = 1/2 ( AB + CD ) × h = 1/2 (25 + 13) × 3√21cm^2 = 57√21 cm^2