Find the area of the quadrilateral formed by joining the points A(-4,8

1.	Find the area of the quadrilateral formed by joining the points A(-4,8),B(-4,2),C(6,-7) and D(-6,1) in order.
Answer» Answer: The SIDES of quadrilateral AB = 6 BC = 13.453624 CD = 14.4222051 AD = 7.28010989 Then, Semi-Perimeter s= 41.155939/2= 20.5779695 The AREA of quadrilateral, A = √(s-a)(s-b)(s-c)(s-d) A = √(20.58-6)(20.58-13.45)(20.58-14.22)(20.58-7.28) A = √(14.587.136.36*13.3) A = √8,793.37938 A = 93.77 SQ UNITS.

Find the area of the quadrilateral formed by joining the points A(-4,8),B(-4,2),C(6,-7) and D(-6,1) in order.

Answer»

Answer:

AB = 6

BC = 13.453624

CD = 14.4222051

AD = 7.28010989

Then,

s= 41.155939/2= 20.5779695

The AREA of quadrilateral,

A = √(s-a)(s-b)(s-c)(s-d)

A = √(20.58-6)(20.58-13.45)(20.58-14.22)(20.58-7.28)

A = √(14.58*7.13*6.36*13.3)

A = √8,793.37938