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Find the area of the shaded parts 50m 40m 1.5m 5m |
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Answer» AnswerLength of rectangle ABCD =50 mBreadth of rectangle ABCD =5 mArea of rectangle ABCD =L×B =50×5 =250 m LENGTH of rectangle EFGH =35 mBreadth of rectangle EFGH =5 mArea of rectangle EFGH =35×5 =175 m Length of rectangle ILKL =5 mBreadth of rectangle IJKL =5 mArea of rectangle IJKL =35×5 =175 m 2 Now,Area of shaded portion = (Area of ABCD + Area of EFGH) − Area of IJKL =(250+175)−25 =425−25 =400 m Hence area of shaded portion is 400 m 2 |
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