Find the area of the shaded portion 30m45m25m50m50m60 m

1.	Find the area of the shaded portion 30m45m25m50m50m60 m
Answer» ANSWER: Answer Length of rectangle ABCD =50 m Breadth of rectangle ABCD =5 m Area of rectangle ABCD =L×B =50×5 =250 m 2 Length of rectangle EFGH =35 m Breadth of rectangle EFGH =5 m Area of rectangle EFGH =35×5 =175 m 2 Length of rectangle ILKL =5 m Breadth of rectangle IJKL =5 m Area of rectangle IJKL =35×5 =175 m 2 Now, Area of shaded portion = (Area of ABCD + Area of EFGH) − Area of IJKL =(250+175)−25 =425−25 =400 m 2 Hence area of shaded portion is 400 m Step-by-step EXPLANATION: i hope help you

Answer»

Answer

Length of rectangle ABCD =50 m

Breadth of rectangle ABCD =5 m

Area of rectangle ABCD =L×B

=50×5

=250 m

Length of rectangle EFGH =35 m

Breadth of rectangle EFGH =5 m

Area of rectangle EFGH =35×5

=175 m

Length of rectangle ILKL =5 m

Breadth of rectangle IJKL =5 m

Area of rectangle IJKL =35×5

=175 m

Now,

Area of shaded portion = (Area of ABCD + Area of EFGH) − Area of IJKL

=(250+175)−25

=425−25

Hence area of shaded portion is 400 m

Step-by-step EXPLANATION:

i hope help you

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