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Find the area of the triangle formed by the lines `y-x=0,x+y=0`and `x-k=0`. |
Answer» Equation of line 1,`L_1->y-x = 0=> x= y->(1)` Equation of line 2,`L_2->x+y = 0=> x = -y->(2)` Equation of line 3,`L_3->x-k = 0=> x = k->(3)` Now, if we draw these lines, it will form a triangle with vertices, `(0,0),(k,k),(k,-k)`. Please refer to video for the diagram. Now, from the diagram, we can see that, Base of triangle `=2k` Altitude of triangle ` = k` So, Area of triangle = 1/2*base*height `:.` Area `= 1/2*2k*k = k^2` square units |
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