1.

Find the area of the triangle with the length of the side 9CM 10 cm and 17 cm​

Answer»

Step-by-step explanation :

To find :-

Area of triangle.

Solution:-

Given,

Sides of triangle are 9 cm, 10cm and 17 cm.

We USE Heron's formula for finding area of triangle because HEIGHT of triangle is not given.

Heron's formula is :

\sf \bold{ Area \: of \: triangle =  \sqrt{s(s - a)(s - b)(s - c)} }

Where,

  • s is semi-perimeter of triangle.
  • a, b and c are sides of triangle.

So,

\sf Semi - perimeter_{(Triangle)} =  \dfrac{Perimeter}{2}  \\  \\  \sf Semi - permeter_{(Triangle)} = \dfrac{36}{2} \\  \\   \sf \blue{Semi - perimter_{(Triangle)} =  \bold{18}}

Semi-perimeter of triangle is 18 cm.

Now,

\sf  \longrightarrow Area_{(Triangle)} =  \sqrt{18 \times (18 - 9)(18 - 10)(18 - 17)}

\sf  \longrightarrow Area_{(Triangle)} =  \sqrt{18 \times 9 \times 8 \times 1}

\sf  \longrightarrow Area_{(Triangle)} =  \sqrt{2 \times 3 \times 3 \times 3 \times 3 \times 2 \times 2 \times 2 \times 1}

\sf  \longrightarrow Area_{(Triangle)} =  2 \times 2 \times 3 \times 3 \times 1

\sf  \longrightarrow \purple{\boxed{\sf \bold{Area_{(Triangle)} = 36}} \bigstar}

THEREFORE,

Area of triangle is 36 cm².



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