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Find the area of triangle ABC formed by the points A (0, 4), (3, 0) and X (4, 0) and show these points on coordinate axis. |
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Answer» Explanation: By distance FORMULA: AC= 0 2 +4 2
=4 AB= 3 2 +0 2
=4 BC= 3 2 +(−4) 2
=5 And s= 2 3+4+5
=6 So area of ΔABC= 6(6−5)(6−4)(6−3)
= 6×1×2×3
=6 |
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