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    				| 1. | Find the area of triangle, whose vertices are (2,3), (7,5) and (-7,-5). | 
| Answer» Area of triangle `=1/2[x_(1)(y_(2)-y_(3))+x_(2)(y_(3)-y_(1))+x_(2)(y_(3)-y_(1))+x_(3)(y_(1)-y_(2))` `=1/2[2(5+5)+7(-5-3)-7(3-5)]=1/2(20-56+14)=-11` But the area of triangle connot be negative `therefore` Area of triangle = 11 square units | |