1.

Find the arithmetic progression whose third term is 16 and the seventh term exceeds its fifth term by 12.

Answer»

Given, in an A.P

a3 = 16 and a7 = a5 + 12

We know that an = a + (n – 1)d

⇒ a + 2d = 16…… (i)

And,

a + 6d = a + 4d + 12

2d = 12

⇒ d = 6

Using d in (i), we have

a + 2(6) = 16

a = 16 – 12 = 4

Hence, the A.P is 4, 10, 16, 22, …….



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