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Find the arithmetic progression whose third term is 16 and the seventh term exceeds its fifth term by 12. |
Answer» Given, in an A.P a3 = 16 and a7 = a5 + 12 We know that an = a + (n – 1)d ⇒ a + 2d = 16…… (i) And, a + 6d = a + 4d + 12 2d = 12 ⇒ d = 6 Using d in (i), we have a + 2(6) = 16 a = 16 – 12 = 4 Hence, the A.P is 4, 10, 16, 22, ……. |
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