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Find the avarage value of current (in A) shown graphically in fig. From `t=0 to t=2 s`. . |
Answer» From the i-t graph, area from t-0 to t=2 =`(1)/(2) xx2 xx 10=10 "Amp. Sec"`. `therfore "Average Current"=(10)/(2)=5"Amp"` |
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