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Find the average binding energy per nucleon of ._7N^14 and ._8O^16. Their atomic masses are 14.008 u and 16.000 u. The mass of ._1H^1atom is 1.007825 u and the mass ofneutron is 1.008665 u. Which is more stable? |
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Answer» Solution :The average binding energy per nucleon `=[[Zm_H+(A-Z)m_n-._zM^A]]/A` The average binding energy per nucleon of `._7N^14` `=([7xx1.007825+7xx1.008665-14.008]uxxc^2)/14` `=[[14.115430-14.008]931.5)/14` MeV `=(0.10743xx931.5)/14` MeV = 7.148 MeV The average binding energy per nucleon of `._8O^16` `=([8xx1.007825+8xx1.008665-16.000]uxxc^2)/A` `=(0.131920xx931.5)/16` MeV= 7.680 MeV `therefore ._8O^16` is more STABLE than `._7N^14` . |
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