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Find the bond order of ` B_2` |
Answer» ` B_2=sigma1s^2,sigma^**1s^2,sigma2s^(2),sigma^**2s^2, [(pi2p_y^1),(pi2p_z^1)]` `:.` Bond order of `B_2 1/2 xx [ 6 - 4 ] =1 `. |
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