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Find the bond order of ` CO` |
Answer» `CO= sigma1s^2, sigma^**1s^2, sigma2s^2, sigma2p_x^2 [(pi2p_y^2),(pi2p_z^2)],sigma^**2s^2` `:.` Bond order of ` CO = 1/2 [ 10 - 4 ] = 3` . |
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