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Find the bond order of ` N_2` |
Answer» `N_2 = sigma1s^2,sigma^**1s^2,sigma2s^(2),sigma^**2s^2 [(pi2p_y^1),(pi2p_z^1)]` , `simga 2 p_s^2` `:.` Bond order of ` N_2 = 1/2 xx [ 10 - 4 ] =3`. |
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