1.

Find the capacitance of the capacitor that would have a reactance of 100 Omega when used with an a.c. source of frequency 5/pi kHz.

Answer»

Solution :Here, `X_(C) = 100 Omega, v= 5/pi kHz = 5000/pi Hz`
`therefore C = 1/(X_(C).2pi) = (1/(100 XX 2pi xx (500)/pi)) = 10^(-4) F = 1 muF`


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