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    				| 1. | Find the cartesian co-ordinates of the points on the parabola y2 = 12x whose parameters are (i) 2(ii) -3 | 
| Answer» Given equation of the parabola is y2 = 12x Comparing this equation with y2 = 4ax, we get 4a = 12 ∴ a = 3 If t is the parameter of the point P on the parabola, then P(t) = (at2 , 2at) i.e., x = at2 and y = 2at …..(i) (i) Given, t = 2 Substituting a = 3 and t = 2 in (i), we get x = 3(2)2 and y = 2(3)(2) x = 12 and y = 12 ∴ The cartesian co-ordinates of the point on the parabola are (12, 12) (ii) Given, t = -3 Substituting a = 3 and t = -3 in (i), we get x = 3(-3)2 and y = 2(3)(-3) x = 27 and y = 18 ∴ The cartesian co-ordinates of the point on the parabola are (27, 18) | |