1.

Find the cartesian co-ordinates of the points on the parabola y2 = 12x whose parameters are (i) 2(ii) -3

Answer»

Given equation of the parabola is y2 = 12x 

Comparing this equation with y2 = 4ax, we get 4a = 12 

∴ a = 3 

If t is the parameter of the point P on the parabola, then 

P(t) = (at2 , 2at)

i.e., x = at2 and y = 2at …..(i) 

(i) Given, t = 2 

Substituting a = 3 and t = 2 in (i), we get 

x = 3(2)2 and y = 2(3)(2) 

x = 12 and y = 12 

∴ The cartesian co-ordinates of the point on the parabola are (12, 12)

(ii) Given, t = -3

Substituting a = 3 and t = -3 in (i), we get 

x = 3(-3)2 and y = 2(3)(-3) 

x = 27 and y = 18

∴ The cartesian co-ordinates of the point on the parabola are (27, 18)



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