InterviewSolution
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InterviewSolution
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Find the cartesian equation of the line which passes through the point `(-2,4,-5)` and parallel to the line `(x+3)/3 = (y-4)/5 = (z+8)/6` |
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Answer» The direction ratios of the line `(x+3)/(3) = (y-4)/(5) = (z+8)/(6)` are `(3,5,6)`. Here the line passes through the point (-2,4,-5) and the direction ratios of the parallel line are `(3,5,6)` . So, the equation of line is, `(x-(-2))/(3) = (y-4)/(5) = (z-(-5))/(6)` `rArr (x+2)/(3) = (y-4)/(5) = (z+5)/(6)` |
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