Find the center and radius of the circle(x + 5)² + (y - 3)² = 36

1.	Find the center and radius of the circle(x + 5)² + (y - 3)² = 36
Answer» ⠀⠀⠀ ՏϴᏞႮͲᏆϴΝ $\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$ The equation ofa circle with CENTRE (h, K) and radius r is given as: $( x - h)^{<klux>2</klux>} + (y - k)^{2} = k^{2}$ It is given that centre (h,k) = (-2, 3) and radius (r) = 4 . Therefore, the equation of the circle is: $(x + 2)^{2} + (y - 3)^{2} = {(4)}^{2}$ $x ^{2} + 4x + 4 \: + {y}^{2} - 6y + 9 = 16$ $x ^{2} + {y}^{2} + 4x - 6y - 3 = 0$ $\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

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