1.

Find the charge on the capacitor in the following circuit.

Answer»

`12muC`
`14muC`
`20muC`
`18muC`

SOLUTION :The capacitor branch will not ALLOW charge to pass through it.
`therefore` Current in the circuit is `I=(12)/(6+2)=(12)/(8)=(3)/(2)A`
Potential DIFFERENCE ACROSS `2muF` is same as across `6Omega` resistance.
`thereforeq=CV=2xx(3)/(2)xx6=18muC`


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