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Find the coefficient of `x^5` in `(1+2x+3x^2...........)^(-3/2)`A. 21B. 25C. 26D. none of these |
Answer» Correct Answer - D `(1+2x+3x^(2)+"……")^(-3//2) =[(1-x)^(-2)]^(-3//2)` `= (1-x)^(3)= 1-3x+3x^(2) - x^(3)` Therefore, coefficientof `x^(5)` is `0` |
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