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Find the components of a vector `A = 2hati + 3hatj` along the directions of `hati + hatj and hati - hatj.` |
Answer» `vecC=(A cos theta)hatB=(vecA.vecB)/(|vecB|)[(vecB/(|vecB|)]` `vecC=[(2+3)/(sqrt(1+1))][(hati+hatj)/(sqrt(1+1))]=(5)/(2)(hati+hatj)`. |
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