1.

Find the components of a vector `A = 2hati + 3hatj` along the directions of `hati + hatj and hati - hatj.`

Answer» `vecC=(A cos theta)hatB=(vecA.vecB)/(|vecB|)[(vecB/(|vecB|)]`
`vecC=[(2+3)/(sqrt(1+1))][(hati+hatj)/(sqrt(1+1))]=(5)/(2)(hati+hatj)`.


Discussion

No Comment Found

Related InterviewSolutions