1.

Find the compound interest when the rate is 6.25% , principal is ₹1275 and time is 1 year​

Answer»

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Compound\:Interest=79.6875\:rupees}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline\bold{<klux>GIVEN</klux> :}} \\  \tt: \implies Principal(p) = 1275\: rupees \\  \\  \tt: \implies Rate\%(r) = 6.25\% \\  \\ \tt :  \implies Time(t) = 1 \: years \\  \\ \red{\underline\bold{To \: Find :}} \\  \tt:  \implies Compound \: Interest = ?

ACCORDING to given QUESTION :

\bold{As \: we \: know \: that} \\  \tt : \implies A =p(1 +   \frac{r}{100} )^{t}  \\  \\ \tt : \implies A =1275(1 +  \frac{6.25}{100} )^{1}  \\  \\ \tt : \implies A =1275 \times (1 + 0.0625) \\  \\ \tt : \implies A =1275 \times 1.0625 \\  \\ \green{\tt : \implies A =1354.6875 \: rupees} \\  \\  \bold{For \: compound \: interest : } \\  \tt : \implies C.I =A- p \\  \\ \tt : \implies C.I =1354.6875 - 1275 \\  \\   \green{\tt : \implies C.I=79.6875 \: rupees}



Discussion

No Comment Found