1.

Find the compound ratio of the inverse ratios of the ratios ` x^(2) : (yz)/x, y^(2) : (zx)/y " and " z^(2) : (xy)/z`.

Answer» The inverse ratios of the ratios ` x^(2) : (yz)/x, y^(2) : (zx)/y " and " z^(2) : (xy)/x : x^(2) , (zx)/y : y^(2) " and " (xy)/z : z^(2) ` respectively.
` :. ` their compound ratio ` = ((yz)/z xx (zx)/y xx (xy)/z) : ( x^(2) xx y^(2) xx z^(2))`
` = xyz : x^(2) y^(2)z^(2)`
` = (xyz)/(x^(2)y^(2)z^(2)) = 1 : xyz`.
Hence the required compound ratio = `1 : xyz`.


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