InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Find the coordinates of a point on `x+y+3=0,`whose distance from `x+2y+2=0`is `sqrt(5)dot` |
|
Answer» Let the required point be P(a,b). Then, `a+b+3=0` `"Also",(|a+2b+2|)/(sqrt(1^(2)+2^(2)))=sqrt5=|a+2b+2|=5` `Rightarrow (a+2b+2=5) or (a+2b+2=-5)` `Rightarrow a+2b=3 or a+2b=-7` `"Thus", a+2b=3......(ii) and a+2b=-7......(iii)` On solving (i) and (ii), we get a=-9 and b=6. On solving (i) and (iii), we get a=1 and b=-4 Hence, the required points are A(-9,6) and B(1,-4). |
|