Saved Bookmarks
| 1. |
Find the coordinates of any point on the parabola whose focus is (0, 1)and directrix is `x+2=0`A. `(t^(2)+1, 2t-1)`B. `(t^(2)+1, 2t+1)`C. `(t^(2), 2t)`D. `(t^(2)-1, 2t+1)` |
|
Answer» Correct Answer - D The equation of the parabola is given by `sqrt((x-0)^(2)+(y-1)^(2))=|(x+2)/(sqrt1+0)|` `rArr" "x^(2)+(y=1)^(2)=(x+2)^(2)` `rArr" "(y-1)^(2)=4(x+1)` The parametrix coordinates of the point of this parabola are given by `x+1=t^(2)" and "y-1=2t" i.e. "(t^(2)-1, 2t+1)` |
|