1.

If a, b, c are distinct positive real numbers such that the parabolas y2 = 4ax and y2 = 4c (x– b) will have a common normal, then(a)   0 < b/a - c < 1(b)   b/a - c < 0(c)  1 <b/a - c < 2(d)  b/a - c > 2

Answer»

Correct option  (d)  b/a - c > 2

Explanation:

Equation of normals are

y = mx –2am – am3 ......(1)

y = m(x – b) – 2cm – cm3 ......(2)

Equation 1 and 2 are identical then

–2am – am3 = –bm –2cm –cm3 / m

2a + am2 = b + 2c + cm2

(a– c)m2 = b + 2(c  – a)

m2 = b/a - c - 2

m = ± √b/a - c - 2

For m be real b/a - c  > 2



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