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If a, b, c are distinct positive real numbers such that the parabolas y2 = 4ax and y2 = 4c (x– b) will have a common normal, then(a) 0 < b/a - c < 1(b) b/a - c < 0(c) 1 <b/a - c < 2(d) b/a - c > 2 |
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Answer» Correct option (d) b/a - c > 2 Explanation: Equation of normals are y = mx –2am – am3 ......(1) y = m(x – b) – 2cm – cm3 ......(2) Equation 1 and 2 are identical then –2am – am3 = –bm –2cm –cm3 / m 2a + am2 = b + 2c + cm2 (a– c)m2 = b + 2(c – a) m2 = b/a - c - 2 m = ± √b/a - c - 2 For m be real b/a - c > 2 |
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