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InterviewSolution
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Find the coordinates of the foci, the vertices, the eccentricity and the length of the latus rectum of the Hyperbola (x^(2))/(16)-(y^(2))/(9)=1 |
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Answer» Solution :`(x^(2))/(16)-(y^(2))/(9)=1` Here,`a^(2)=16,b^(2)=9rArra=4,b=3` `:."Vertices"-=(pma,0)-=(pm4,0)` ECCENTRICITY `e=SQRT(1+(b^(2))/(a^(2)))=sqrt(1+(9)/(16))=(5)/(4)` Coordinates of foci `-=(pmae,0)-=(pm5,0)` Latus rectum `=(2b^(2))/(a)=(2xx9)/(4)=(9)/(2)` |
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