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| 1. |
Find the cube of 7 by the sum of consecutive odd number |
| Answer» LET the FIRST odd integer be x. therefore , x+x+2+x+4+x+6+x+8+x+10+x+12=7^3 x+x+2+x+4+x+6+x+8+x+10+x+12= 343 => 7X + 42 = 343 7x=301 x=301/7 x=43 therefore , 43+45+47+49+51+53+55= 343 or, 43+45+47+49+51+53+55=7^3 Step-by-step explanation:let the first odd integer be x. therefore , x+x+2+x+4+x+6+x+8+x+10+x+12=7^3 x+x+2+x+4+x+6+x+8+x+10+x+12= 343 => 7x + 42 = 343 7x=301 x=301/7 x=43 therefore , 43+45+47+49+51+53+55= 343 or, 43+45+47+49+51+53+55=7^3 | |