Find the curl of A = (y cos ax)i + (y + e^x)k(a) 2i – ex j – cos ax k(b) i – ex j – cos ax k(c) 2i – exj + cos ax k(d) i – ex j + cos ax kThe question was asked during an internship interview.Question is from Vector Calculus topic in chapter Vector Calculus of Electromagnetic Theory

Find the curl of A = (y cos ax)i + (y + e^x)k(a) 2i – ex j – cos a

1.	Find the curl of A = (y cos ax)i + (y + e^x)k(a) 2i – ex j – cos ax k(b) i – ex j – cos ax k(c) 2i – exj + cos ax k(d) i – ex j + cos ax kThe question was asked during an internship interview.Question is from Vector Calculus topic in chapter Vector Calculus of Electromagnetic Theory
Answer» Correct ANSWER is (b) i – ex J – cos AX k The best EXPLANATION: Curl A = i(Dy(y + ex)) – j (Dx(y + ex) – Dz(y cos ax)) + k(-Dy(y cos ax)) = 1.i – j(ex) – k cos ax = i – ex j – cos ax k.

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Find the curl of A = (y cos ax)i + (y + e^x)k(a) 2i – ex j – cos ax k(b) i – ex j – cos ax k(c) 2i – exj + cos ax k(d) i – ex j + cos ax kThe question was asked during an internship interview.Question is from Vector Calculus topic in chapter Vector Calculus of Electromagnetic Theory

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