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Find the current flowing across three resistors 3 Omega, 5 Omega and 2 Omega, connected in parallel to a 15 V supply. Also find the effective resistance and total current drawn from the supply. |
Answer» SOLUTION :![]() Effective resistance of PARALLEL combination `(1)/(R_(P)) = (1)/( R _(1)) + (1)/( R _(1)) + (1)/( R _(3))` `= 1/3 + 1/5 + 1/2` `R_(P) = 0.96 77 Omega` Current through `R _(1), I _(1) = (V)/( R _(1)) = (15)/(3) =5 A` Current through `R _(2), I _(2) = ( V)/(R _(2)) = (15)/( 5 ) = 3 A` Current through `R_(3), I _(3) = ( V)/( R _(3)) = (15)/(2) = 7.5 A` Total current `I = (V )/( R _(P)) = (15)/( 0.96 77) = (15)/( 0.96 77) = 15.5A` |
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