InterviewSolution
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InterviewSolution
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Find the current in each cell considering circuit given in fig. |
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Answer» SOLUTION :Applying kirchhoff.s law for the loop ABCDA `6= 40i + (i_1 + i_2)10` `6= 40i_1 + 10i_1 + 10i_2` `6= 50i_1 + 10i_2""….(1)` For the loop DCFED  `2=10(i_2 + i_2) + 50i_2` `2 = 10i_1 + 10i_2 + 50i_2` `2 = 10 i_1 + 60 i_2""......(2)` From (1) and (2) `290 i_1 = 34` `i_1 = 0.1172 A ""......(3)` Substituting (3) in (2) `2 = 10 xx 0.1172 + 60i_2 , 2= 1.172 + 60i_2` `60i_2 = 2 - 1.172 , i_2 = (2-1.172)/(60) =0.0138 A` CURRENT in the 6V cell = 0.1172 A Current in the cell = 0.0138 A |
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