1.

Find the current through resistor R.

Answer»

9A
10A
11A
8A

Solution :`R_(EQ)=12/31+1=52/31Omega`
`i=(20xx31)/52A`
`i_(1)=i_(2):i_(3)=1/3:1/1:1/7=7:21:3`
`i_(2)=21/31xx(20xx31)/52=(21xx20)/52=105/13=8A`


Discussion

No Comment Found

Related InterviewSolutions