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Find the curve for which the length of normal is equal to the radiusvector. |
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Answer» Correct Answer - `y^(2)+-x^(2)=c` Length of normal `=ysqrt(1+((dy)/(dx))^(2))` and radius vector `=sqrt(x^(2)+y^(2))` `therefore y^(2)[1+((dy)/(dx))^(2)]=x^(2)+y^(2)` or `y(dy)/(dx) =+-x` or `ydy+-xdx=0` or `y^(2)+-x^(2)=c` |
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