1.

Find the diameter and the circumference of a circle whose area is :A) 394.24cm²B) 25pi cm²Plz explain me the answer fast

Answer»

GIVEN:-

  • Area of CIRCLE is 394.24 cm².
  • Area of circle is 25 pi cm².

To find:-

  • Diameter and circumference of a circle.

Solution:-

1) 394.24 cm²

\large{\tt{\longmapsto{Area = 394.24}}}

\large{\tt{\longmapsto{\pi r^2 = 394.24}}}

\large{\tt{\longmapsto{\dfrac{22}{7} \times r^2 = 394.24}}}

\large{\tt{\longmapsto{r^2 = \dfrac{394.24 \times 7}{22}}}}

\large{\tt{\longmapsto{r^2 = \dfrac{2759.68}{22}}}}

\large{\tt{\longmapsto{r^2 = 125.44}}}

\large{\tt{\longmapsto{r = \sqrt 125.44}}}

\large{\tt{\longmapsto{r = 11.2}}}

\large{\tt{\longmapsto{Perimeter = 2 \pi r}}}

\large{\tt{\longmapsto{2 \times \dfrac{22}{7} \times 11.2}}}

\large{\tt{\longmapsto{44 \times 1.6}}}

\large{\tt{\longmapsto{\boxed{\red{70.4}}}}}

Hence,

  • Diameter = 2r = 22.4 CM
  • Perimeter = 70.4 cm

2) 25 pi cm²

\large{\tt{\longmapsto{Area = 25 \times \pi}}}

\large{\tt{\longmapsto{\pi r^2 = 25 \times \pi}}}

\large{\tt{\longmapsto{r^2 = 25}}}

\large{\tt{\longmapsto{r = \sqrt 25}}}

\large{\tt{\longmapsto{r = 5}}}

\large{\tt{\longmapsto{Perimeter = 2 \pi r}}}

\large{\tt{\longmapsto{2 \times \dfrac{22}{7} \times 5}}}

\large{\tt{\longmapsto{\dfrac{44}{7} \times 5}}}

\large{\tt{\longmapsto{\boxed{\red{31.42}}}}}

Hence,

  • Diameter = 2r = 10 cm
  • Perimeter = 31.42 cm


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