1.

Find the dispersive power of a prism, given that n_(v) = 1.657 and n_(R) = 1.631.

Answer»

Solution :`n_(v) = 1.657, "" n_(R) = 1.631"" OMEGA = (n_(v) - n_(R))/(n - 1)`
` n = (n_(v) + n_(R))/(2) = (1.657 + 1.631)/(2) = 1.644`
`THEREFORE omega(1.657 - 1.631)/(1.644 - 1) = (0.026)/(0.644) = (0.0404)`


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