1.

Find the dispersive power of flint glass if the refractive indices of flint for red, green and violet light are 1.613, 1.620 and 1.632 respectively.

Answer»

SOLUTION :GIVE: `n_(v) = 1.632 , n_(R) = 1.620`
Equation for DISPERSIVE POWER is ,`omega=((n_(v)-n_(n)))/((n_(G)-1))`
Substituting the values, `omega=(1.632-1.613)/(1.620-1)=(0.019)/(1.620)=0.0306`
The dispresive power of flint glass is, `omega = 0.306`


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