Find the dissociation coefficient of an aqueous potassium chloride solution with a concentration of 0.1g//cm^(3) if the resistivity of this solution at 18^(@)C is 7.36xx10^(-2) ohm.m. The mobility of the potassium ions is 6.7xx10^(-8)m^(2)//(V.s) that of the chlorine ions 6.8xx10^(-8)m^(2)//(V.s)

Find the dissociation coefficient of an aqueous potassium chloride sol

1.	Find the dissociation coefficient of an aqueous potassium chloride solution with a concentration of 0.1g//cm^(3) if the resistivity of this solution at 18^(@)C is 7.36xx10^(-2) ohm.m. The mobility of the potassium ions is 6.7xx10^(-8)m^(2)//(V.s) that of the chlorine ions 6.8xx10^(-8)m^(2)//(V.s)
Answer» SOLUTION :The electrical conductivity of an electrolyte is `gamma=qn(b_(+)+ +b_(-))=alphaqn_(0)(b_(+)+b_(-))`, where `ALPHA` is the dissociation coefficient sought. The CHARGE of a monovalent ion is q=e. The concentration of the solutionis `C=m_(0)n_(0)=Mn_(0)//N_(A)`, where M is the MOLAR mass of the dissolved substance. Substituting these values, we OBTAIN `alpha=(gammaM)/(eCN_(A)(b_(+)+b_(-)))`

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Find the dissociation coefficient of an aqueous potassium chloride solution with a concentration of 0.1g//cm^(3) if the resistivity of this solution at 18^(@)C is 7.36xx10^(-2) ohm.m. The mobility of the potassium ions is 6.7xx10^(-8)m^(2)//(V.s) that of the chlorine ions 6.8xx10^(-8)m^(2)//(V.s)

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