1.

Find the distance between adjacent interference bands if the distance from the source to biprism is 1 m and from biprism to screen is 4 m.The angle of refraction of biprism is 2 xx 10^(-3) rad. How many interference bands can be observed on the screen ? (Given mu = 1.5 & lambda = 6000 Å)

Answer»

5
4
3
2

Solution :`d= 2(mu - 1). A . L = 2(1.5 - 1) xx 2 xx 10^(-3) xx 1 = 2 xx 10^(-3)`m

`D = 4 + 1 = 5 m`
`beta = (lambda.D)/(d) = 15 xx 10^(-4)` m
If N = number of fringes
Then `N = (L)/(beta)`, where L is width of interference PATTERN
From fig.
`(L)/(d) = (b)/(a)`
`therefore L = (b)/(a) xx d = 4/1 xx 2 xx 10^(-3) = 8 xx 10^(-3)`
`N = (8 xx 10^(-3))/(15 xx 10^(-4)) = 5.3 APPROX 5`.


Discussion

No Comment Found

Related InterviewSolutions