1.

Find the distance between `P(x_1, y_1)a n d Q(x_2, y_2)`when i. `P Q`is parallelto the y-axis ii. PQ is parallel to the x-axis.

Answer» Correct Answer - (i) `|x_(2)-x_(1)|` (ii) `|y_(2)-y_(1)|`
(i) When AB is a parallel to the x-axis, then A and B have the same ordinate.
Then, `A(x_(1),y) and B(x_(2),y)` are the given points. So, AB`=|x_(2)-x_(1)|`
(ii) When AB is parallel to the y-axis. Then A and B have the same abscissa. Then, `A(x,y_(1)) and B(x,y_(2))` are the given points. So, AB=`|y_(2)-y_(1)|`


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