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Find the distance between `P(x_1, y_1)a n d Q(x_2, y_2)`when i. `P Q`is parallelto the y-axis ii. PQ is parallel to the x-axis. |
Answer» Correct Answer - (i) `|x_(2)-x_(1)|` (ii) `|y_(2)-y_(1)|` (i) When AB is a parallel to the x-axis, then A and B have the same ordinate. Then, `A(x_(1),y) and B(x_(2),y)` are the given points. So, AB`=|x_(2)-x_(1)|` (ii) When AB is parallel to the y-axis. Then A and B have the same abscissa. Then, `A(x,y_(1)) and B(x,y_(2))` are the given points. So, AB=`|y_(2)-y_(1)|` |
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