Find the distance between the parallel lines 3y + 4x - 12 = 0 and 3y +

1.	Find the distance between the parallel lines 3y + 4x - 12 = 0 and 3y + 4x - 7 = 0.1. 12. 23. 34. 4
Answer» Correct Answer - Option 1 : 1 Concept: The distance between the parallel lines ax + by + c₁ and ax + by + c₂ is: D = \(\rm \left\|c_1-c_2\over\sqrt{a^2+b^2}\right\|\) Calculation; The 2 given lines are: 3y + 4x - 12 = 0 3y + 4x - 7 = 0 a = 4, b = 3, c₁ = -12 and c₂ = -7 ∴ The distance between the lines D = \(\rm \left\|c_1-c_2\over\sqrt{a^2+b^2}\right\|\) ⇒ D = \(\rm \left\|-12-(-7)\over\sqrt{4^2+3^2}\right\|\) ⇒ D = \(\rm \left\|-5\over5\right\|\) = 1

Find the distance between the parallel lines 3y + 4x - 12 = 0 and 3y + 4x - 7 = 0.1. 12. 23. 34. 4

Answer» Correct Answer - Option 1 : 1

Concept:

The distance between the parallel lines ax + by + c₁ and ax + by + c₂ is:

D = \(\rm \left|c_1-c_2\over\sqrt{a^2+b^2}\right|\)

Calculation;

The 2 given lines are:

3y + 4x - 12 = 0

3y + 4x - 7 = 0

a = 4, b = 3, c₁ = -12 and c₂ = -7

∴ The distance between the lines

D = \(\rm \left|c_1-c_2\over\sqrt{a^2+b^2}\right|\)

⇒ D = \(\rm \left|-12-(-7)\over\sqrt{4^2+3^2}\right|\)

⇒ D = \(\rm \left|-5\over5\right|\) = 1