Find the distance between the parallel lines p(x+y)+g=0 and p(x+y)-r=0

1.	Find the distance between the parallel lines p(x+y)+g=0 and p(x+y)-r=0.
Answer» Correct Answer - `(\|q+r\|)/(sqrt2p` Putting x=0 in px+py+q=0, we get y=(-q/p) Required distance=length of perp. From `P(0,(-q)/(p))` on px+py-r=0 `(\|pxx0+pxx((-q)/(p))-r\|)/(sqrt(p^(2))+p^(2))=(\|-q-r\|)/(sqrt2p)=(\|q+r\|)/(sqrt2p)`

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Find the distance between the parallel lines p(x+y)+g=0 and p(x+y)-r=0.

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