1.

Find the distance between the parallel lines y=mx+c and y=mx+d.

Answer» Correct Answer - `(|d-c|)/(sqrt(1+m^(2)))`
Putting x=0 in y=mx+c, we get y=c.
Thus, P(0,c) is a point on y=mx+c
Required distance=length of perp. From P(0,c) on y=mx+d
`(|mxx0-c+d|)/(sqrt(1+m^(2)))=(|d-c|)/(sqrt1+m^(2))`


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