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Find the distance between the parallel lines y=mx+c and y=mx+d. |
Answer» Correct Answer - `(|d-c|)/(sqrt(1+m^(2)))` Putting x=0 in y=mx+c, we get y=c. Thus, P(0,c) is a point on y=mx+c Required distance=length of perp. From P(0,c) on y=mx+d `(|mxx0-c+d|)/(sqrt(1+m^(2)))=(|d-c|)/(sqrt1+m^(2))` |
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