InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Find the distance betweenthe line `(x+1)/(-3)=(y-3)/2=(z-2)/1`and the plane `x+y+z+3=0.` |
|
Answer» The line is along the vector `veca= - 3hati+2hatj+hatk ` and plane is normal to the vector `vecb= hati+hatk+hatk`. Since `veca*vecb = 0` , the line is parallel to the plane. Hence, the distance between the line and the plane is the distance of point `(-1, 3, 2)` from the plane, `" "(|-1+3+2+3|)/(sqrt(1+1+1))= (7)/(sqrt(3))` |
|