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Find the distance of the point (-1,1) and the given line is `12x-5y+82=0` |
Answer» The given point is P(-1,1) and the given line is 12x-5y+82=0. Let the required distance be d. The, d=length of the perpendicular from P(-1,1) on the line 12-5y+82=0 `=(|12xx(-1)-5xx1+82|)/(sqrt((12)^(2)+(-5)^(2)))=(65)/(sqrt169)=(65)/(13)=5units` |
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