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Find the distance of the point `(21,0)`from the plane `2x+y+2z+5=0.`A. `10/3`B. `5/3`C. `10/9`D. none of these |
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Answer» Correct Answer - A We know that the distance of the point `(x_(1),y_(1),z_(1))` from the plane `ax+by+cz+d=0` is `(|ax_(1)+by_(1)+cz_(1)+d|)/(sqrt(a^(2)+b^(2)+c^(2))` So, required distance `=(|2xx2+1+2xx0+5|)/(sqrt(2^(2)+1^(2)+2^(2)))=10/3` |
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